Thus, we obtain 2.72 12 5 L x L =≈ − . (b) A sketch of the field lines is shown in the figure below: 8. (a) The individual magnitudes GE1 and G E2 are figured from Eq. 22-3, where the absolute value signs for q2are unnecessary since this charge is positive. Whether we add the magnitudes or subtract them depends on if GE1 is in the same, or opposite, direction as G E2 . At points left of q 1(on the – x axis) the fields point in opposite directions, but there is no possibility of cancellation (zero net field) since GE1 is everywhere bigger than G E2 in this region. In the region between the charges (0 < x<
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This note was uploaded on 06/07/2010 for the course PHYS 344 taught by Professor Bb during the Summer '10 term at The Petroleum Institute.