ch22-p015 - 15. (a) The electron ec is a distance r = z =...

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15. (a) The electron e c is a distance r = z = 0.020 m away. Thus, 92 2 1 9 6 22 0 (8.99 10 N m C )(1.60 10 C) 3.60 10 N/C 4 (0.020 m) C e E r πε ×⋅ × == = × . (b) The horizontal components of the individual fields (due to the two e s charges) cancel, and the vertical components add to give 2 1 9 s,net 3 / 2 2 2 3 / 2 0 6 2 2(8.99 10 N m C )(1.6 10 C)(0.020 m) 4 ( ) [(0.020 m) (0.020 m) ] 2.55 10 N/C . ez E Rz × ++ (c) Calculation similar to that shown in part (a) now leads to a stronger field 4 3.60 10 N/C c E from the central charge. (d) The field due to the side charges may be obtained from calculation similar to that
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This note was uploaded on 06/07/2010 for the course PHYS 344 taught by Professor Bb during the Spring '10 term at The Petroleum Institute.

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