ch22-p018 - 18. According to the problem statement, Eact is...

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Unformatted text preview: 18. According to the problem statement, Eact is Eq. 22-5 (with z = 5d) Eact = q q 160 q − = ⋅ 2 2 4πε 0 (4.5d ) 4πε 0 (5.5d ) 9801 4πε 0 d 2 and Eapprox is Eapprox = 2qd 2 q = ⋅ . 3 4πε 0 (5d ) 125 4πε 0 d 2 The ratio is Eapprox Eact = 0.9801 ≈ 0.98. ...
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This note was uploaded on 06/07/2010 for the course PHYS 344 taught by Professor Bb during the Summer '10 term at The Petroleum Institute.

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