25. From symmetry, we see that the net field at Pis twice the field caused by the upper semicircular charge +=⋅qRλπ(and that it points downward). Adapting the steps leading to Eq. 22-21, we find ()90net229000ˆˆ2jsinj.4qERRθεε°−°⎛⎞=−=−⎜⎟
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This note was uploaded on 06/07/2010 for the course PHYS 344 taught by Professor Bb during the Spring '10 term at The Petroleum Institute.