where
R
is the radius of the disk and
σ
is the surface charge density on the disk. See Eq.
2226. The magnitude of the field at the center of the disk (
z
= 0) is
E
c
=
/2
ε
0
. We want
to solve for the value of
z
such that
E
/
E
c
= 1/2. This means
22
11
1.
zz
zR
−=
⇒
=
++
Squaring both sides, then multiplying them by
z
2
+
R
2
, we obtain
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 Spring '10
 BB
 Physics, Charge, Electric charge, Fundamental physics concepts, 0.600 m, Uniformly Charged Disk, LM N, 0.346 m

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