ch22-p035 - 35. At a point on the axis of a uniformly...

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where R is the radius of the disk and σ is the surface charge density on the disk. See Eq. 22-26. The magnitude of the field at the center of the disk ( z = 0) is E c = /2 ε 0 . We want to solve for the value of z such that E / E c = 1/2. This means 22 11 1. zz zR −= = ++ Squaring both sides, then multiplying them by z 2 + R 2 , we obtain
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