ch29-p012 - 12. With the usual x and y coordinates used in...

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0 22 3 / 2 4( ) iR ds dB sR µ π = + . (a) Clearly, considered as a function of s (but thinking of “ ds ” as some finite-sized constant value), the above expression is maximum for s = 0. Its value in this case is 2 max 0 /4 dB i ds R = . (b) We want to find the s value such that max /10 dB dB = . This is a non-trivial algebra exercise, but is nonetheless straightforward. The result is
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This note was uploaded on 06/08/2010 for the course PHY 1356 taught by Professor Bonamente during the Spring '10 term at UAA.

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