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(c) and
(d) Fig. 2945(b) shows that as we get very
close to wire 2 (where its field
strongly dominates over that of the more distant wire 1)
B
y
points along the –
y
direction.
The righthand rule leads us to conclude that wire 2’s current is consequently is
into the
page
.
We previously observed that the currents were in opposite directions, so wire 1’s
current is
out of the page
.
14. The fact that
B
y
= 0 at
x
= 10 cm implies the currents are in opposite directions.
Thus
01
02
02
41
2(
) 2
2
y
ii
i
B
Lx
x
Lxx
µµ
µ
ππ
π
⎛⎞
=−
=
−
⎜⎟
++
⎝⎠
using Eq. 294 and the fact that
12
4
ii
=
. To get the maximum, we take the derivative with
respect to
x
and set equal to zero.
This leads to 3
x
2
– 2
Lx
–
L
2
= 0 which factors and
becomes (3
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This note was uploaded on 06/08/2010 for the course PHY 1356 taught by Professor Bonamente during the Spring '10 term at UAA.
 Spring '10
 Bonamente

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