ch29-p025

ch29-p025 - angle θ′ = 53.13º – 20º = 33.13º. Thus,...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
25. We use Eq. 29-4 to relate the magnitudes of the magnetic fields B 1 and B 2 to the currents ( i 1 and i 2 , respectively) in the two long wires. The angle of their net field is θ = tan 1 ( B 2 / B 1 ) = tan 1 ( i 2 / i 1 ) = 53.13º. The accomplish the net field rotation described in the problem, we must achieve a final
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: angle θ′ = 53.13º – 20º = 33.13º. Thus, the final value for the current i 1 must be i 2 /tan = 61.3 mA....
View Full Document

This note was uploaded on 06/08/2010 for the course PHY 1356 taught by Professor Bonamente during the Spring '10 term at UAA.

Ask a homework question - tutors are online