27. The contribution to netBGfrom the first wire is (using Eq. 29-4) 760111(410 T m/A)(30 A)ˆˆˆkk(3.0 10 T)k.22 (2.0 m)iBrµππ−−π×⋅===×GThe distance from the second wire to the point where we are evaluating netBGis r2= 4 m −2 m = 2 m. Thus, 760222(410 T m/A)(40 A)ˆ
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This note was uploaded on 06/08/2010 for the course PHY 1356 taught by Professor Bonamente during the Spring '10 term at UAA.