This preview shows page 1. Sign up to view the full content.
34. We note that when there is no
y
component of magnetic field from wire 1 (which, by
the righthand rule, relates to when wire 1 is at 90º =
π
/2 rad), the total
y
component of
magnetic field is zero (see Fig. 2962(c)).
This means wire #2 is either at
+
π
/2 rad
or
−π
/2 rad.
(a) We now make the assumption that wire #2 must be at
−π
/2 rad (
−
90º, the bottom of
the cylinder) since it would pose an obstacle for the motion of wire #1 (which is needed
to make these graphs) if it were anywhere in the top semicircle.
(b) Looking at the
θ
1
= 90º datum in Fig. 2962(b)) – where there is a
maximum
in
B
net
x
(equal to +6
µ
T) – we are led to conclude that
1
6.0 T
2.0 T
4.0 T
x
B
µ
µµ
=
−=
in that
situation.
Using Eq. 294, we obtain
6
1
1
7
0
2
2 (0.200 m)(4.0 10 T)
4.0 A
This is the end of the preview. Sign up
to
access the rest of the document.
This note was uploaded on 06/08/2010 for the course PHY 1356 taught by Professor Bonamente during the Spring '10 term at UAA.
 Spring '10
 Bonamente

Click to edit the document details