fullwood (tf5349) – Homework Fluids – Catala – (49033)
1
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printout
should
have
22
questions.
Multiplechoice questions may continue on
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before answering.
001
10.0 points
An engineer weighs a sample of mercury (
ρ
=
13
.
6
×
10
3
kg
/
m
3
) and finds that the weight
of the sample is 4
.
1 N.
What is the sample’s volume? The acceler
ation of gravity is 9
.
81 m
/
s
2
.
Correct answer: 3
.
07309
×
10

5
m
3
.
Explanation:
Let :
W
= 4
.
1 N
,
ρ
= 13
.
6
×
10
3
kg
/
m
3
,
and
g
= 9
.
81 m
/
s
2
.
m
=
W
g
so
V
=
m
ρ
=
W
g ρ
=
4
.
1 N
(9
.
81 m
/
s
2
)(13
.
6
×
10
3
kg
/
m
3
)
=
3
.
07309
×
10

5
m
3
.
002
10.0 points
A pipe contains water at 4
.
9
×
10
5
Pa above
atmospheric pressure.
If you patch a 4
.
1 mm diameter hole in the
pipe with a piece of bubble gum, how much
force must the gum be able to withstand?
Correct answer: 6
.
46925 N.
Explanation:
Let :
P
= 4
.
9
×
10
5
Pa
and
r
= 2
.
05 mm
.
P
=
F
A
F
=
P A
=
P
(
π r
2
)
= (4
.
9
×
10
5
Pa)
π
(2
.
05 mm)
2
parenleftbigg
1 m
1000 mm
parenrightbigg
2
=
6
.
46925 N
.
003
(part 1 of 2) 10.0 points
A container is filled with water to a depth of
32
.
8 cm. On top of the water floats a 28
.
7 cm
thick layer of oil with a density of 637 kg
/
m
3
.
What is the absolute pressure at the surface
of the water?
The acceleration of gravity is
9
.
81 m
/
s
2
.
Correct answer: 1
.
02793
×
10
5
Pa.
Explanation:
Let :
h
o
= 28
.
7 cm
,
ρ
o
= 637 kg
/
m
3
,
g
= 9
.
81 m
/
s
2
,
and
P
0
= 1
.
01
×
10
5
Pa
.
P
=
P
0
+
ρ
o
g h
o
= 1
.
01
×
10
5
Pa
+ (637 kg
/
m
3
) (9
.
81 m
/
s
2
)
×
(28
.
7 cm)
parenleftbigg
1 m
100 cm
parenrightbigg
=
1
.
02793
×
10
5
Pa
.
004
(part 2 of 2) 10.0 points
What is the absolute pressure at the bottom
of the container?
Correct answer: 1
.
06011
×
10
5
Pa.
Explanation:
Let :
h
w
= 32
.
8 cm
and
ρ
w
= 1000 kg
/
m
3
.
P
net
=
P
+
ρ
w
g h
w
= 1
.
02793
×
10
5
Pa
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fullwood (tf5349) – Homework Fluids – Catala – (49033)
2
+ (1000 kg
/
m
3
) (9
.
81 m
/
s
2
)
×
(32
.
8 cm)
parenleftbigg
1 m
100 cm
parenrightbigg
=
1
.
06011
×
10
5
Pa
.
005
10.0 points
The Mariana Trench, in the Pacific Ocean, is
about 11 km deep.
If
atmospheric
pressure
at
sea
level
is
1
.
01
×
10
5
Pa and the density of sea water
is 1025 kg
/
m
3
, how much pressure would a
submarine need to be able to withstand to
reach this depth? The acceleration of gravity
is 9
.
81 m
/
s
2
.
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 Spring '10
 PRO.KIROSHIMA
 Work, Correct Answer, Orders of magnitude

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