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# solution5 - fullwood(tf5349 – Quizzes 2 Electric Field...

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Unformatted text preview: fullwood (tf5349) – Quizzes 2 Electric Field and Potential – Catala – (12054) 1 This print-out should have 7 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 (part 1 of 2) 10.0 points Two point charges of magnitude 8 . 32 nC and- 4 . 29 nC are separated by 39 cm. The acceleration of gravity is 9 . 8 m / s 2 . The Coulomb constant is 8 . 98755 × 10 9 N · m 2 / C 2 . What is the electric potential at a point midway between the charges? Correct answer: 185 . 743 V. Explanation: Let : q 1 = 8 . 32 nC = 8 . 32 × 10- 9 C , q 2 =- 4 . 29 nC =- 4 . 29 × 10- 9 C , r = 39 cm = 0 . 39 m , r 1 = r 2 = r 2 , and k e = 8 . 98755 × 10 9 N · m 2 / C 2 . The electric potential is V = V 1 + V 2 = k e r 1 q 1 + k e r 2 q 2 = 2 k e r ( q 1 + q 2 ) = 2 (8 . 98755 × 10 9 N · m 2 / C 2 ) . 39 m × bracketleftbig (8 . 32 × 10- 9 C) + (- 4 . 29 × 10- 9 C) bracketrightbig = 185 . 743 V ....
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solution5 - fullwood(tf5349 – Quizzes 2 Electric Field...

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