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03_InstSolManual_PDF

# 03_InstSolManual_PDF - MOTION IN A PLANE 3 Answers to...

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3-1 M OTION IN A P LANE 3 Answers to Multiple-Choice Problems 1. B 2.A 3. C 4. C 5.A 6. B 7. B 8.A 9. C 10. C 11.A 12. C 13. D 14. B 15. D 16. B 17. B Solutions to Problems 3.1. Set Up: Since distances are given in km, use as units for velocity. Solve: (a) (b) and its components are shown in Figure 3.1. Figure 3.1 and below the axis. 3.2. Set Up: Since the velocity is expressed in units of and the time interval is in seconds, it is convenient to express the acceleration in mixed units of Solve: (a) (b) and its components are shown in Figure 3.2. Figure 3.2 and below the 1 x -axis. f 5 13.2°, tan f 5 1 v y 2 av 1 v x 2 av a av 5 " 1 a x 2 av 2 1 1 a y 2 av 2 5 820 km / h # s; 1 a x 2 a v 1 a y 2 a v a a v f y x O a S av 2 18.7 km / h # s 1 a y 2 av 5 D v y D t 5 365 km / h 2 415 km / h 6.52 s 2 3.85 s 5 1 a x 2 av 5 D v x D t 5 838 km / h 2 625 km / h 6.52 s 2 3.85 s 5 79.8 km / h # s; km / h # s. km / h 1 x f 5 12.4 ° , tan f 5 1 v y 2 av 1 v x 2 av v av 5 " 1 v x 2 av 2 1 1 v y 2 av 2 5 1.12 km / s; 1 v x 2 a v v a v 1 v y 2 a v y x f O v S av 1 v y 2 av 5 D y D t 5 0.925 km 2 1.20 km 1.14 s 5 2 0.24 km / s 1 v x 2 av 5 D x D t 5 6.24 km 2 5.00 km 1.14 s 5 1.09 km / s; km / s

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3.3. Set Up: Coordinates of point A are and for point B they are Solve: (a) At A , (b) and its components are shown in Figure 3.3a. and counterclock- wise from the Figure 3.3 (c) (d) and its components are shown in Figure 3.3b. and counterclockwise from the the Reflect: The displacement of the dragon fl y is in the direction of 3.4. Set Up: The time to travel from point A to point B is 1.50 s, as given in Problem 3.3. Solve: (a) (b) and its components x and y are shown in Figure 3.4. and counterclockwise from the Figure 3.4 f 1 a y 2 a v 1 a x 2 a v a a v x y O 1 x -axis. f 5 124 ° , tan f 5 1 v y 2 av 1 v x 2 av a av 5 " 1 a x 2 av 2 1 1 a y 2 av 2 5 2.54 m / s 2 ; a S av 1 a y 2 av 5 D v y D t 5 8.26 m / s 2 5.11 m / s 1.50 s 5 2.10 m / s 2 1 a x 2 av 5 D v x D t 5 4.05 m / s 2 6.20 m / s 1.50 s 5 2 1.43 m / s 2 ; v S av . 1 x -axis. f 5 32 ° , tan f 5 1 v y 2 av 1 v x 2 av v av 5 " 1 v x 2 av 2 1 1 v y 2 av 2 5 6.2 m / s; v S av 1 v y 2 av 5 D y D t 5 6.0 m 2 1.0 m 1.50 s 5 3.3 m / s 1 v x 2 av 5 D x D t 5 10.0 m 2 2.0 m 1.50 s 5 5.3 m / s; ( b ) O 1 v x 2 a v 1 v y 2 a v v a v y x f ( a ) r u y y O x x 1 x -axis. u 5 26.6 ° , tan u 5 y x r 5 " x 2 1 y 2 5 2.2 m; r S y 5 1.0 m. x 5 2.0 m, 1 10.0 m, 6.0 m 2 . 1 2.0 m, 1.0 m 2 3-2 Chapter 3
3.5. Set Up: The coordinates of each point are: A , B , C , D , At each point the velocity is tangent to the circular path, as shown in Figure 3.5. The components of the velocity at each point are: A , B , C , D , Figure 3.5 Solve: (a) A to B The time for one full lap is A to B is one-quarter lap and takes (b) A to C (c) C to D (d) A to A so and so (e) For A to B , The speed is constant so the average speed is The average speed is larger than the magnitude of the average velocity because the distance traveled is larger than the displacement. (f) Velocity is a vector, with both magnitude and direction. The magnitude of the velocity is constant but its direction is changing.

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03_InstSolManual_PDF - MOTION IN A PLANE 3 Answers to...

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