Chapter 6

Chapter 6 - Chapter 6 solutions See figures of output...

Info iconThis preview shows pages 1–13. Sign up to view the full content.

View Full Document Right Arrow Icon
Chapter 6 solutions See figures of output signals, next page Æ
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
6.3, continued -0.04 -0.02 0 0.02 0.04 -0.5 0 0.5 1 1.5 a t -0.04 -0.02 0 0.02 0.04 -0.5 0 0.5 1 1.5 b t -0.04 -0.02 0 0.02 0.04 -0.5 0 0.5 1 1.5 c t -0.04 -0.02 0 0.02 0.04 -0.5 0 0.5 1 1.5 d t -0.04 -0.02 0 0.02 0.04 -0.5 0 0.5 1 1.5 e t -0.04 -0.02 0 0.02 0.04 -0.5 0 0.5 1 1.5 f t
Background image of page 2
Transfer Fcn 1 0.0016 s+1 Scope 1 Scope Pulse Generator Part (a)
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Part (b) Part (c)
Background image of page 4
Part (d) Part (e)
Background image of page 5

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Part (f)
Background image of page 6
Background image of page 7

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 8
6.9 Continued Æ
Background image of page 9

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
6.9(a), continued (b) (c)
Background image of page 10
6.11 (a) (Note that you don’t need the “Analog Butterworth LP Filter” block; just use a Transfer Function block with the coefficients derived from the ‘ butter(N, Wn, ‘s’) ’ command.) We should select a cutoff frequency for the low-pass filter so that the oscillations in the signal are eliminated as much as possible. This doesn’t specify a precise criterion, however. Here is the signal before and after filtering with a 2 nd order Butterworth low-pass filter with ω c =100 π : The next output plot uses ω c =20 π , giving a smoother result, although it takes longer to get there: (b) Here is the signal after filtering with a 4 th order Butterworth filter with ω c =20 π :
Background image of page 11

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
6.11, (c)
Background image of page 12
Image of page 13
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 06/10/2010 for the course ECES 302 taught by Professor Carr during the Spring '08 term at Drexel.

Page1 / 34

Chapter 6 - Chapter 6 solutions See figures of output...

This preview shows document pages 1 - 13. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online