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Unformatted text preview: 3 A Current is 1.25*103 A P = V*I = 1.25 V * 1.25*103 A = 1.5625*103 W Power dissipated is 1.5625*103 W 2) f(t)=exp(at), g(t)=cos( ϖ t) = de atdt = ae at = cosωtdt = ( ) sin ωt ω +c 3) x+3y=1…….(i) 2xy=2……. .(ii) Multiplying (i) by 2 and subtracting it from (ii) gives7y=0 or y=0 and x=1...
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 Spring '09
 Volt, 3 W, 202 Sec, Pramit Bhattacharya

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