{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

problem_pdf - dang(rtd356 – HW05 – li –(59050 This...

Info icon This preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
dang (rtd356) – HW05 – li – (59050) 1 This print-out should have 27 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0 points If a metal wire carries a current of 100 mA, how long does it take for 13.0 × 10 20 electrons to pass a given cross-sectional area anywhere along the wire? The magnitude of the charge on an electron is 1 . 6 × 10 19 C. Answer in units of s. 002 (part 1 of 2) 10.0 points The current in a conductor varies over time as shown in the figure. 0 1 2 3 4 5 6 7 0 1 2 3 4 5 6 0 1 2 3 4 5 6 7 0 1 2 3 4 5 6 Current(A) Time(s) How much charge passes through a cross section of the conductor in the time interval t = 0 s to t = 2 s? Answer in units of C. 003 (part 2 of 2) 10.0 points What constant current would transport the same total charge during the 2 s interval as does the actual current? Answer in units of A. 004 10.0 points The current in a wire decreases with time according to the relationship I = (3 . 99 mA) × e at where a = 0 . 13328 s 1 . Determine the total charge that passes through the wire from t = 0 to the time the current has diminished to zero. Answer in units of C. 005 (part 1 of 3) 10.0 points Consider two cylindrical conductors made of the same ohmic material. Conductor 1 has a radius r 1 and length 1 while conductor 2 has a radius r 2 and length 2 . Denote: The currents of the two conductors as I 1 and I 2 , the potential differences between the two ends of the conductors as V 1 and V 2 , and the electric fields within the conductors as E 1 and E 2 .
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}