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# Ch. 3 - Silberberg Chapter 3 Stoichiometry as there are...

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Silberberg, Chapter 3 Stoichiometry (Review) 3.1 The Mole (mol): the amount of a substance that contains the same number of entities as there are atoms in exactly 12 grams of 12 C. 1 mol of a substance represents a fixed number of chemical entities and has a fixed mass 1 mol contains 6.022 x 10 23 entities (to 4 s.f.) a.k.a Avagadro s number The molecular mass (or formula mass) of a compound expressed in amu (atomic mass units) is numerically the same as the mass of 1 mol of the compound expressed in grams (e.g. 1 mol of H 2 O (6.022 x 10 23 molecules) has a mass of 18.02 g. Molar mass ( M ): the mass per mole of its entities in units of grams per mole (g/mol) Use the periodic table to find the molar mass for elements and to calculate the molar mass of compounds. Interconverting units: Moles, Mass and Number of chemical entities Mass (g) = no. of moles x molar mass (g/mol) No. of moles = mass (g) / molar mass (g/mol) No. of entities = no. of moles x 6.022 x 10 23 entities/mol Mass Percent from the Chemical Formula Mass % of element X = moles of X in formula x molar mass (g/mol) mass (g) of 1 mol of compound

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3.2 Determining the Formula of an Unknown Compound
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Ch. 3 - Silberberg Chapter 3 Stoichiometry as there are...

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