Ch. 9, 10 - Ionic-Lewis WS Key

# Ch. 9, 10 - Ionic-Lewis WS Key - Ionic Bonding and Lewis...

This preview shows pages 1–2. Sign up to view the full content.

Ionic Bonding and Lewis Structure Worksheet 1. Use the Born-Haber cycle to calculate the lattice energy of KF. K(s) K(g) H ° = 90 kJ K(g) K + (g) + e H ° = 419 kJ F 2 (g) 2F(g) H ° = 159 kJ H Lattice = 830 kJ K(s) + ½ F 2 (g) KF(s) H ° f = -569 kJ F(g) + e F - (g) H ° = -328 kJ 2. Use the Born-Haber Cycle to calculate the electron affinity of NaCl. Na(s) Na(g) H ° = 109 kJ Cl 2 (g) 2Cl(g) H ° = 243 kJ Na(g) Na + (g) + e H ° = 496 kJ EA= -427 kJ Na(s) + ½ Cl 2 (g) NaCl(s) H ° f = -411 kJ Na + (g) + Cl - (g) NaCl(s) H ° = -711 kJ 3. Arrange the following in order of increasing lattice energy and explain your answer: a. MgS, MgO, MgSe MgSe<MgS<MgO larger ionic radius, smaller lattice energy b. AlCl 3 , NaCl, MgCl 2 NaCl<MgCl 2 <AlCl 3 larger the charge, larger lattice energy 4. Using the bond dissociation energies, calculate the H ° rxn for the following reaction: a. CH 4 (g) + Cl 2 (g) CH 3 Cl(g) + HCl(g) b. C 2 H 2 (g) + H 2 (g) C 2 H 4 (g) a. H rxn = 4(413 kJ/mol) + 1(243 kJ/mol) – [3(413 kJ/mol) + 1(339 kJ/mol) + 1(427 kJ/mol)= -110. kJ b. H rxn = 2(413 kJ/mol) + 1(839 kJ/mol) + 1(432 kJ/mol) – [1(614 kJ/mol) + 4(413

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern