Exam 1 - Review Solutions

Exam 1 - Review Solutions - (f) (4+13-1)/52 = 16/52 (g)...

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STATISTICS 321 – Exam 1 Review SOLUTIONS 1. (a) B C (b) A C (c) B C (d) A C C 2. (a) Draw a tree as done in class. (b) Not independent. If the first flight is delayed, the probability of luggage getting to Denver in time is smaller. (c) P(luggage on time)= P(luggage on time AND first flight on time) + P(luggage on time AND first flight delayed)= ( . 15)( . 95) + ( . 85)( . 65) = 0 . 695 3. 5/24 = 0 . 21 4. (a) 890/1929 (b) 421/1929 (c) 593/986 5. (a) 4/52, 13/52, 12/52 (b) no (c) no (d) yes (e) (4+12)/52 = 16/52
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Unformatted text preview: (f) (4+13-1)/52 = 16/52 (g) (13+12-3)/52 = 22/52 (h) (4+13+12 - 1-3)/52 = 25/52 6. (a) (.8)(.86)= .688 (b) (.8)(.86)+(.2)(.35) = .758 (c) .688/.758 = .908 7. At least 75% of the customers spend between $70 and $310. 8. Section 2.4: 10 (All other answers given at the back of the book) (a) (.9) (b) (.1)(.9) (c) P ( X = 3) = ( . 1)( . 1)( . 9) (d) P ( X = x ) = p ( x ) = ( . 1) x-1 ( . 9) , for x = 1 , 2 ,,. .. 1...
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This note was uploaded on 06/15/2010 for the course CHEM 124 taught by Professor Hascall during the Winter '08 term at Cal Poly.

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