Experiment 10 - For Sample 1 it has =702.805x10^6...

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Experiment 10: Introduction to Flame Atomic Absorption Spectroscopy (Determination of Copper) Aim: To determine the concentration of copper in various samples. Introduction: Atomic absorption spectroscopy is a method of determining the concentration of a metal element in a sample. It occurs because atoms of an element will absorb radiant energy specific wavelengths and that the amount of energy absorbed is proportional to the number of absorbing atoms in the light path. Results: Calibrat ion Standar d (ug/ml) Absorba nce 0 0.0000 1000 0.3305 1500 0.4820 2000 0.6185
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Brass Calibration Absorbance vs Concentration y = 0.0003x + 0.0077 R 2 = 0.9982 0.0000 0.1000 0.2000 0.3000 0.4000 0.5000 0.6000 0.7000 0 500 1000 1500 2000 2500 Concentration (ug/ml) Absorbance Calculations were done on the concentrations obtained from the AAS machine readout instead of using the graph. Sample 1 and 2 are from one type of brass and sample 3 and 4 are from another type of brass. 250ml of solvent was used to dissolve the sample of brass thus:
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Unformatted text preview: For Sample 1 it has: =702.805x10^6 =7.02805x10^-4 g/ml of Copper =7.02805x10^-4 x 250 Sample Weight of Brass (g) Concentrat ion (ug/ml) Absorban ce SD 1 0.3142 702.805 0.2341 0.7 2 0.3018 689.211 0.2296 0.5 3 0.3012 678.006 0.2259 0.5 4 0.3052 679.154 0.2263 0.5 =0.175701g of Cu in 0.3142g of Brass = 0.175701/0.3142*100 = 55.92% For Sample 2: =689.211x10^6 =6.89211x10^-4 g/ml of Copper =6.89211x10^-4 x 250 =0.172303g of Cu in 0.3018g of Brass = 0.169502/0.3018*100 =57.09% For Sample 3: =678.006x10^6 =6.78006x10^-4 g/ml of Copper =6.78006x10^-4 x 250 =0.169502g of Cu in 0.3012g of Brass = 0.169502/0.3018*100 = 56.28% For Sample 4: =679.154x10^6 =6.79154x10^-4 g/ml of Copper =6.79154x10^-4 x 250 =0.169789g of Cu in 0.3052g of Brass = 0.169789/0.3052*100 =55.63% Average: Brass Sample 1 Brass Sample 2 =(55.92+57.09)/2 =(56.28+55.63)/2 =56.51% =55.96%...
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Experiment 10 - For Sample 1 it has =702.805x10^6...

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