This preview shows pages 1–4. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: MS&E 352 Handout #23 Decision Analysis II Mar 04, 2009 ______________________________________________________________________ ______________________________________________________________________ 03/07/06 Page 1 of 9 Problem Set #3 Problem Set #3 Solutions Grade Distribution 0% 5% 10% 15% 20% 25% 30% 35% 05 610 1115 1620 2125 2630 3135 3640 4145 4650 5155 5660 6165 6670 7175 7680 8185 8690 9195 96100 Problem 1 Discretization Practice [30 points] We designed this problem to give you practice in discretizing continuous distributions (here, a Gaussian or normal distribution), as well as to show you the accuracy of the different discretization methods. Willie Wafer, sole proprietor of Big Chip Little Chip Semi Conductors, faces an alternative whose net present value (NPV) has a normal distribution with mean of $0 and standard deviation of 1 million dollars. Willie follows the delta property and has a risk tolerance of 5 million dollars. You will find the cumulative distribution for Willie's alternative on the attached page (You can generate this for yourself using the NORMDIST function in Excel). You will compare the distributions and certain equivalents, which result from the different discretization methods. MS&E 352 Handout #23 Decision Analysis II Mar 04, 2009 ______________________________________________________________________ ______________________________________________________________________ 03/07/06 Page 2 of 9 Problem Set #3 Question 1: [20 points] Fill out the table on the following page. If you want partial credit, show your work on the momentmatching discretizations on a separate page. Answer: See table on next page. Error Codes: [1.1.1] 2 to 5 points At least one PISP calculation is wrong. [1.1.2] 1 to 7 points Mistake in or missing results for one of the two methods. [1.1.3] 1 point Minor mistake in the PISP calculations, such as: a) wrong sign; or b) because you did not exactly compute the probabilities of each degree (e.g. typed 0.33 instead of 1/3 for 3 degrees), your PISPs are slightly off; or c) used a probability distribution for the equal areas method that did not make sense; d) rounded off all the answers, so it was impossible to compare accuracy; e) used incorrect risk tolerance MS&E 352 Handout #23 Decision Analysis II Mar 04, 2009 ______________________________________________________________________ ______________________________________________________________________ 03/07/06 Page 3 of 9 Problem Set #3 A closed form equation exists to find the certain equivalent of a normal distribution, given its mean and variance....
View
Full
Document
This note was uploaded on 06/16/2010 for the course MS&E 352 taught by Professor Ronhoward during the Winter '09 term at Stanford.
 Winter '09
 RONHOWARD

Click to edit the document details