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Unformatted text preview: B ˙ ILKENT UNIVERSITY Department of Mathematics MATH 225, LINEAR ALGEBRA and DIFFERENTIAL EQUATIONS, Solution of Homework set 1 # 20 U. Mu˘gan July 4, 2008 Homework problems from the 2 nd Edition, SECTION 6.1 3 (3) ) 2 The characteristic eq. p ( λ ) = λ 2 7 λ + 10 = 0 . Therefore, the eigenvalues are λ 1 = 2 , λ 2 = 5 . The eigenvectors for λ 1 = 2: 6 v 11 6 v 12 = 0 3 v 11 3 v 12 = 0 ~v 1 = • 1 1 ‚ For λ 2 = 5: 3 v 21 6 v 22 = 0 3 v 21 6 v 22 = 0 ~v 2 = • 2 1 ‚ 6 (6) ) The characteristic eq. p ( λ ) = λ 2 5 λ + 6 = ( λ 2)( λ 3) = 0 . Therefore, the eigenvalues are λ 1 = 2 , λ 2 = 3 . The eigenvectors for λ 1 = 1: 4 v 11 4 v 12 = 0 3 v 11 3 v 12 = 0 ~v 1 = • 1 1 ‚ For λ 2 = 3: 3 v 21 4 v 22 = 0 3 v 21 4 v 22 = 0 ~v 2 = • 4 3 ‚ 1 I made every effort to avoid the calculation errors and/or typos while I prepared the solution set. You are responsible to check all the solutions and correct the errors if there is any. If you find any errors and/or...
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This note was uploaded on 06/18/2010 for the course COMPUTER S Math 225 taught by Professor Yosumhoca during the Spring '10 term at Bilkent University.
 Spring '10
 YosumHoca

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