CE%203400HW20-Solution%20Fall%202009

CE%203400HW20-Solution%20Fall%202009 - The University of...

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The University of Texas Department of Civil Engineering CE 357 - Homework No. 21 - SOLUTION Bearing Capacity of Footings on Clay Problem 1: ul t cc q ' Ndc = ⋅⋅ f c D 5 d 1 0. 2 1 0. 2 1.13 B8 = + = += u q 2 c 1 ts f 2000 psf 22 = = == ( 29( 29( 29 ult q ' 5.1 4 1.1 3 200 0 11,60 0 psf ult safe q' 11,600 q 3870 F3 = psf Problem 2: ul t ccc q ' NdSc = ⋅⋅⋅ f c D4 0. 2 1 0. 2 1.13 B6 = + = c S 1 0. 2 1 0. 2 1.2 L6 = + = ( 29( 29( 29( 29 ult q ' 5.1 4 1.1 3 1. 2 250 0 17,400 psf ult safe q ' 17,400 q 5800 psf = ( 29 ( 29( 29 2 2 saf e safe Load, Q qB 580 0 6 209,000pound s 209kips = = If the top 4 feet of soil were sand, the depth correction factor (d c ) would not be applied, i. e. d c = 1, because the sand would have a lower strength than the clay (normal stresses, σ , are low in the sand; thus, the strength of the sand is low).
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CE%203400HW20-Solution%20Fall%202009 - The University of...

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