CE%203400HW20-Solution%20Fall%202009

# CE%203400HW20-Solution%20Fall%202009 - The University of...

This preview shows pages 1–2. Sign up to view the full content.

The University of Texas Department of Civil Engineering CE 357 - Homework No. 21 - SOLUTION Bearing Capacity of Footings on Clay Problem 1: ul t cc q ' Ndc = ⋅⋅ f c D 5 d 1 0. 2 1 0. 2 1.13 B8 = + = += u q 2 c 1 ts f 2000 psf 22 = = == ( 29( 29( 29 ult q ' 5.1 4 1.1 3 200 0 11,60 0 psf ult safe q' 11,600 q 3870 F3 = psf Problem 2: ul t ccc q ' NdSc = ⋅⋅⋅ f c D4 0. 2 1 0. 2 1.13 B6 = + = c S 1 0. 2 1 0. 2 1.2 L6 = + = ( 29( 29( 29( 29 ult q ' 5.1 4 1.1 3 1. 2 250 0 17,400 psf ult safe q ' 17,400 q 5800 psf = ( 29 ( 29( 29 2 2 saf e safe Load, Q qB 580 0 6 209,000pound s 209kips = = If the top 4 feet of soil were sand, the depth correction factor (d c ) would not be applied, i. e. d c = 1, because the sand would have a lower strength than the clay (normal stresses, σ , are low in the sand; thus, the strength of the sand is low).

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 2

CE%203400HW20-Solution%20Fall%202009 - The University of...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online