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CE%203400%20HW18-Solution%20Fall%202009

# CE%203400%20HW18-Solution%20Fall%202009 - The University of...

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The University of Texas Department of Civil Engineering CE 357 - Homework No. 19 - SOLUTION Shear Strength of Sand Problem 1: tan τ=σ φ 2 N 1000 250 A2 σ= = = psi () 250 tan32 156 psi 22,500 psf τ= °= = Problem 2: Part (a) tan φ 50 tan39 40.5 psi Part (b) 2 13 3 1s i n tan 45 220 psi 21 s i n φ+ φ æö σ=σ + = ç÷ −φ èø 220 50 170 psi σ−σ= = You can also work this graphically as shown below: 100 200 300 100 200 0 0 39º σ 1 = 220 σ 3 = 50 σ τ Problem 3: tan φ 5500 arctan arctan 28.8 29 10000 τ æ ö φ == = ° ° ç ÷ σ è ø φ is low; I would expect this to be a (very) loose sand.

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Problem 4: 2 13 3 1s i n
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CE%203400%20HW18-Solution%20Fall%202009 - The University of...

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