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CE%203400%20HW17-Solution%20Fall%202009

# CE%203400%20HW17-Solution%20Fall%202009 - orientation of...

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The University of Texas Department of Civil Engineering Assigned: Mon., 11 Nov. 2002 (Wright) Due: Mon. 18 Nov. 2002 (Wright) CE 357 - Homework No. 18 State of Stress - Mohr's Circle Problem 1 : Part (a) See Mohr's circle on next page. Part (b) See Mohr's circle on next page. σ 1 = 3150 psf σ 3 = 1350 psf Part (c) See Mohr's circle on next page for values and orientation of planes. τ max = 900 psf Part (d) See Mohr's circle on next page. σ = 2460 psf τ = 875 psf

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σ 3 direction σ 1 direction Pole orientation of plane of maximum shear stress orientation of plane of maximum shear stress point on Mohr's circle representing stresses on a 55º plane 4000 2500 1000 1500 500 1000 2000 2000 0 3000
Problem 2 : Part (a) See below. Part (b) See below. τ max = 2500 psf Part (c) See below. σ = 8750, τ = 2165 psf orientation of minor principal plane

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Unformatted text preview: orientation of major principal plane (horizontal) Pole point τ max = 2500 psf 60º Stresses on 60º plan σ = 8750psf, τ = 2165 2000 4000 2000 4000 6000 8000 10000 1000 3000 5000 Problem 3 : Part (a) See below. Part (b) See below: σ 1 = 6750 psf, σ 3 = 2750 psf Part (c) See below: σ = 5430 psf, τ = ± 1900 psf Pole point ( σ = 4500, τ = 2000) orientation of major principal plane (horizontal) 2000 4000 2000 4000 6000 8000 1000 3000 5000 ( σ = 5000, τ = 2000) ( σ = 3000, τ = 1000) σ 3 = 2750 σ 1 = 6750 σ 1 (direction) σ 3 (direction) Stress on plane making angle of 35º with major principal plane ( σ = 5430, τ = -1900) Stress on plane making angle of 35º with major principal plane ( σ = 5430, τ = 1900) 35º 35º...
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