CE%203400%20HW15-Solution%20Fall%202009

# CE%203400%20HW15-Solution%20Fall%202009 - CE 235 Homework...

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Page 1 of 3 CE 235 - Homework No. 16 - SOLUTION Settlement of Footings on Sand Problem 1 : Part (a) N corr = 30 ( ) () w w f 234 D C 0.5 0.5 0.5 0.5 0.8 DB 3 21 0 ++ =+ = + 1" w corr q0 . 1 1 C N = ( ) ( ) 1" w corr q 0.11 C N 0.11 0.8 30 2.64 == = tsf ( ) 2 2 0.5" Q q B 0.5 2.64 10 132 = ⎡⎤ ⎣⎦ tons = 264 kips Part (b) N corr = 30 ( ) w w f 0 D C 0.5 0.5 0.5 0.5 0.5 3 0 = + 1" w corr . 1 1 C N = ( ) ( ) 1" w corr q 0.11 C N 0.11 0.5 30 1.65 = tsf ( ) 2 2 0.5" Q q B 0.5 2.64 10 132 = tons = 264 kips ( ) 2 2 0.5" Q q B 0.5 1.65 10 82.5 = tons = 165 kips

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Page 2 of 3 Problem 2 : N corr = 20 () 2 2 Q Q 150 q4 . 1 7 AB 6 == = = ksf = 2.08 tsf Part (a) ( ) w w f 4 D C 0.5 0.5 0.5 0.5 0.7 DB 2 26 =+ = ++ + ( ) ( ) 1" w corr q 0.11 C N 0.11 0.7 20 1.54 = 1" q2 . 0 8 S1 . 3 5 q1 . 5 4 = inches Part (b) D w > D f + B, thus C w = 1 ( ) ( ) 1" w corr q 0.11 C N 0.11 1.0 20 2.20 = 1" . 0 8 S0 . 9 5 . 2 0 = Part (c) Yes, I would be concerned about the depth of the water table. If the water table is deep, the settlement should be less than one-inch, which is acceptable for typical buildings. However, if the water table is shallow the settlement may exceed 1 inch, which may not be acceptable for many buildings.
Page 3 of 3 Problem 3 : We must first correct the N values for the effects of overburden pressure. Because the footing is 7 ft x 7 ft and 4 ft deep I will average N values for the 4 ft to 11 ft depth range,
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CE%203400%20HW15-Solution%20Fall%202009 - CE 235 Homework...

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