ASSIGNMENT 1

ASSIGNMENT 1 - Assignment.1 solution January, 16, 2010 MATH...

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Assignment.1 solution January, 16, 2010 MATH 203 2.29 Solution : (a) From the graph, the approximate percentage of aftershocks measuring between 1.5 and 2.5 is 6%+14%+19%+15%+11%+8%=73% (b) From the graph, the approximate percentage of aftershocks measuring greater than 3 is 3%+2%+1.5%+1.25%+.75%+.5%+.30%=9.3% The percentages are obtained by reading oﬀ the heights of the rectangles between the points (these give the percentages). The answer is only an approximation if the two points do not fall as boundary points of their respective intervals, since you do not know where the points are distributed within each interval. 2.37 Solution : (a) They are not symmetrically distributed, since we can see we have more observation around 6 while the data mean median and mode are not the same. 1

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Assignment.1 solution January, 16, 2010 MATH 203 The mean is 7.3, the median is 6.15, and the modes are 5.5, 7, 10.4 and 14.5. so it’s a muplti-modal. so we can’t say the data are symmetrically distributed. (b) As we can see even in the histogram, those large observation are unusual which made the distribution skewed. 2.59 Solution : (a) The mean of the data is ¯ x = x n = 11 . 77 8 = 1 . 4713 (b) The median is the average of the middle two numbers once the data are arranged in order are: 1.37,1.41,1.42,1.48,1.50,1.51,1.53,1.55 The middle two numbers are 1.48 and 1.50. The median is
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This note was uploaded on 06/23/2010 for the course MATH 203 taught by Professor Dr.josecorrea during the Spring '08 term at McGill.

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ASSIGNMENT 1 - Assignment.1 solution January, 16, 2010 MATH...

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