2010 Midterm Exam Solution V.1

# 2010 Midterm Exam Solution V.1 - Midterm.1 solution Winter,...

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Unformatted text preview: Midterm.1 solution Winter, 2010 MATH 203 Q1 Solution : (i) ¯ x = ∑ 13 i =1 x i = (10 . 2 + ··· + 10 . 4) / 13 = 8 . 1 Sample median = 8.5 = middle observation after ordering the observa- tion from smallest to largest. (ii) Median is preferred since the mean is influenced by the two rather small observations 1.1 and 1.3 (iii) The original data were in hours and the latter data were in minutes. The s.d. of the latter data, when the data we converted to hours is 65 . 23 / 60 ≈ 1 . 1. The standard deviation of the original data certainly not much less than 1.1. (In fact, it is 3.4744). So watch out for the units of measurement. Q2 Solution : Clearly the fish-in-the-lake problem, with N = 532+64 = 596, a=64, n=20. (i) P ( exactly 2) = ( 64 2 )( 532 18 ) ( 596 20 ) (ii) P ( at least 2) = 1- P ( less than 2) = 1- [ P ( exactly 0) + P ( exactly 1)] = 1- [ ( 64 )( 532 20 ) ( 596 20 ) + ( 64 1 )( 532 19 ) ( 596 20 ) ] Q3 Solution : Let E = event crash is due to human error M = event crash is due to mechanical failure.M = event crash is due to mechanical failure....
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## This note was uploaded on 06/23/2010 for the course MATH 267815 taught by Professor Wolfson,d during the Spring '10 term at McGill.

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2010 Midterm Exam Solution V.1 - Midterm.1 solution Winter,...

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