SU09-ENG17-midterm-sol

SU09-ENG17-midterm-s - UNIVERSITY OF CALIFORNIADAVIS DEPARTMENT OF ELECTRICAL AND COMPUTER ENGINEERING ENG17 CIRCUITS I SUMMER SESSION I 2009

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UC Davis 1 Hussain Al-Asaad UNIVERSITY OF CALIFORNIA—DAVIS D EPARTMENT OF E LECTRICAL AND C OMPUTER E NGINEERING ENG17 — C IRCUITS I — S UMMER S ESSION I — 2009 M IDTERM E XAM — S OLUTION S TUDENT I NFORMATION I NSTRUCTIONS • The exam is closed book and closed notes. • One double-sided cheat sheet is allowed. • Calculators are allowed. • Print your name and your ID number. • There are six problems in the exam. Choose five problems and solve them. • Cross out the problem that you did not choose. • Show your work for partial credit. • If you need more space for your solution, use the back of the sheets. E XAM G RADE Name Hussain Al-Asaad ID Number xxx-xx-xxxx Problem Maximum Points Student Score 12 0 2 0 22 0 2 0 32 0 2 0 42 0 2 0 52 0 2 0 62 0 2 0 Total 100 100
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UC Davis 2 Hussain Al-Asaad 1. E QUIVALENT R ESISTANCE (20 POINTS ) 1. Find the equivalent resistance R eq (in terms of R ) of the network shown below. 2. Find the equivalent resistance R eq (in terms of R ) of the network shown below. Since none of the resistors are in series or parallel, then it is not possible to combine the resistors to get the equiv- alent resistance. Instead, we can insert a voltage source V s and measure R eq as: Applying KCL at node a, we get . Applying KVL at loop a-b-d, we get . Applying KVL at loop a-c-d, we get . Adding the above two equations, we get . R eq R R R R R 2 R R 2 R R eq 2 R () R 2 R || || = 1 R ------- 1 2 R ------ 1 R --- 1 2 R ++ 1 R 4 2 R R R 2 0.5 R == R eq R R R R R R R R R R + V s i s i 1 i 2 i i 1 i i 2 + i a b c d R V s i s ----- = i s i 1 i 2 + = Ri 1 1 i V s +0 = 2 2 i + V s = 2 1 2 2 2 V s 2 1 i 2 + 2 V s –0 2 s 2 V s V s i s R R R =
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UC Davis 3 Hussain Al-Asaad 2. D EPENDENT V OLTAGE S OURCES (20 POINTS ) It is known that the power absorbed by the resistor between terminals a and b is 9 W. Determine the value of m . . Applying KVL for loop c-a-e, we get: . Applying KVL for loop a-b-e, we get: .
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This note was uploaded on 06/28/2010 for the course ECE ENG 17 taught by Professor Al-asaad during the Summer '09 term at UC Davis.

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SU09-ENG17-midterm-s - UNIVERSITY OF CALIFORNIADAVIS DEPARTMENT OF ELECTRICAL AND COMPUTER ENGINEERING ENG17 CIRCUITS I SUMMER SESSION I 2009

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