lecture14

# lecture14 - Lecture 14 Wednesday February 25 EE 332...

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Lecture 14 Wednesday February 25 EE 332 Semiconductor Devices Problem Assignment Monday ! 4.1 and 4.5 Wednesday ! 5.6 Friday ! 5.7 and 5.8 Finding Relations Using Charge Equality D n A p N w A q N w A q Q = = Charge on each side= ( ) D n A n n p n p D n A p N w N w w w w w w w w N w N w = = = + = Thus or but D A A n N N wN w + = D A p n N N w w / / = p n Using Gauss’s Law to Find the Electric Field in the Depletion Region Gauss’s law for electric fields says the surface integral of the normal component of (electric field times permittivity) over any closed surface equals the charge enclosed. ξ r ε In the n-material at x n0 there is no electric field because the yellow box has no charge. Gauss’s Law Evaluation of the Electric Field (cont.) With the blue box, there is no field at x n as before, and the field at the top and bottom edges is zero by symmetry. Thus the only surface with a contribution is the one through the depletion region. Evaluating Gauss’s law yields at x=x 0 , which is clearly the point of

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