lecture14 - Lecture 14 Wednesday February 25 EE 332...

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Lecture 14 Wednesday February 25 EE 332 Semiconductor Devices Problem Assignment Monday ! 4.1 and 4.5 Wednesday ! 5.6 Friday ! 5.7 and 5.8 Finding Relations Using Charge Equality D n A p N w A q N w A q Q = = Charge on each side= () D n A n n p n p D n A p N w N w w w w w w w w N w N w = = = + = Thus or but D A A n N N wN w + = D A p n N N w w / / = p n Using Gauss’s Law to Find the ElectricFieldintheDepletionRegion Gauss’s law for electric fields says the surface integral of the normal component of (electric field times permittivity) over any closed surface equals the charge enclosed. ξ r ε In the n-material at x n0 there is no electric field because the yellow box has no charge. Gauss’s Law Evaluation of the Electric Field (cont.) With the blue box, there is no field at x n as before, and the field at the top and bottom edges is zero by symmetry. Thus the only surface with a contribution is the one through the depletion region. Evaluating Gauss’s law
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This note was uploaded on 06/30/2010 for the course EECE 332 taught by Professor Constable during the Spring '08 term at Binghamton.

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lecture14 - Lecture 14 Wednesday February 25 EE 332...

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