Chem 115 Final 07

Chem 115 Final 07 - Test Form B1 Name Chemistry 115-S...

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Unformatted text preview: Test Form B1 Name _________________________ Chemistry 115-S Section ____________ FINAL EXAM Total Points = 210 TA ___________________________ Tuesday, 10:20 AM December 11, 2007 THIS EXAM IS FOR STUDENTS WITH TUESDAY-THURSDAY 8:30 or 9:30 LECTURE. YOU SHOULD HAVE A RED COMPUTER ANSWER SHEET! Directions: 1. Each student is responsible for following directions. Read this page carefully. 2. Write your name and other requested information on this page and on the separate answer sheet. 3. CODE your name on the answer sheet using an ordinary (#2) pencil. 4. CODE your correct 10-digit identification number (PUID) on the answer sheet. THIS IS VERY IMPORTANT! 5. CODE your section number on the answer sheet. Please use all four digits, 0101, 0102, 0201, etc. This is also very important! 6. CODE the test number shown in the upper right-hand corner of this page onto the answer sheet in the block labeled “Test Form” under the Date line at the top right-hand side. This is Test Form B1. 7. Put all calculations on the examination pages. DO NOT PUT ANY EXTRA MARKS ON THE COMPUTER ANSWER SHEET! 8. This exam consists of 35 multiple-choice questions worth 6 points each. Choose the one best or correct answer for each question and write it both on your exam paper and on the computer answer sheet. The computer answer sheet is the only one that will be graded! 9. This exam consists of 9 pages plus a Table of Useful Information, a Periodic Table and 2 sheets of scratch paper. Please check to be sure that you have them all! KEEP YOUR ANSWERS AND WORK COVERED TO PROTECT THE INTEGRITY OF YOUR WORK!! 115-S − Final Exam (Test B1) − 12/11/07 _____ 1. How many mL of O 2 measured at 752 mm Hg and 23.0 o C are expected from the complete decomposition of 3.00 g of H 2 O 2 ? 2 H 2 O 2 (ℓ) →2 H 2 O(ℓ) + O 2 (g) (a) 1.08 mL (b) 128 mL (c) 1080 mL (d) 84.1 mL (e) 28.1mL _____ 2. A pair of students found that an average of 0.2991 g of sodium carbonate (105.9888 g/mol) was required to react with 25.00 mL of HCl solution. Given the balanced chemical equation below, calculate the concentration of the HCl solution. Na 2 CO 3 (s) + 2 HCl (aq) → N 2 NaCl(aq) + CO 2 ( g ) + H 2 O(ℓ) (a) 0.1411 M (b) 0.2258 M (c) 0.1336 M (d) 0.05644 M (e) 0.1129 M _____ 3. How many atoms of Americium-241 were in a smoke detector that contained 2.0 x 10 −4 mg of Americium-241 when it was first made? [ 241 Am = 241.0047 amu]. This radionuclide decays via alpha emission and has a half life of 432.2 years....
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Chem 115 Final 07 - Test Form B1 Name Chemistry 115-S...

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