Handout26Inversions

Handout26Inversions - Male ClB/Y = dead and X m/Y = dead therefore no males Female ClB/X = alive and X m/X = alive(If mutation is not lethal then

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BIS101/Engebrecht Handout26-Use of inversions to suppress recombination “Balancer Chromosomes” A) Muller 1927 Xrays are mutagenic Treat males with Xrays, test if Xray induced mutation on male X ClB/+ x X/Y C = chromosome inversion (on X) l = recessive lethal B = BAR dominant B) P: ClB/+ x X m /Y F1: BAR female dead male ClB/X m ClB/Y Female male +/X m +/Y Therefore, BAR females should be heterozygous for induced mutation on X. C) ClB/X m x X/Y If X m is a recessive lethal mutation
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Unformatted text preview: Male ClB/Y = dead and X m /Y = dead; therefore, no males Female ClB/X = alive and X m /X = alive (If mutation is not lethal, then expect 2 female:1 male ratio) D) Suppression of recombination in female by inversion: BAR lethal ----------- ClB/X m 1 8 7 6 5 4 3 2 9 1 2 3 4 5 6 7 8 9 -------------> m Any recombinants between inversion and chromosome carrying the mutation will be inviable. Therefore, transfer of X m through female without change....
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This note was uploaded on 07/02/2010 for the course BIS 101 taught by Professor Simonchan during the Spring '08 term at UC Davis.

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