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InClassLecture27 - 5—?0 Determine the resultant fl of...

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Unformatted text preview: 5—?0 Determine the resultant fl of the system of distributed loads and locate its line of action with respect to the left support for the bean shown in Fig. P5-70. _II' Fig. P5-70 SOLUTION _ l _ 11 — 21750112) _ 750 N _ g _ xc1 - 3(2) - 1.333 m _ l _ A2 - 21750114) - 1500 N _ 1 _ xcz - 2 + 314) _ 3.333 m R = 2F = A1 + A2 = 750 + 1500 = 2250 N R = 2.25 kN Ans. + C ”A = A1xc1 + Aaxcz ?50(1.333) + 1500(3.333l = 6000 N‘I M d = -fi — §999 = 2.6? . ~4 Ans. Rd A R ‘ 2500 II I: 5-?4 Determine the resultant R of the system of distributed loads and locate its line of action with respect to the left support for the been shown in Fig. P5—74. SOLUTION A1 = 400(2.5} = 1000 N RC! = 1.25 m A2 = 400(2-5} = 1000 N xcz = 3.75 I _ l _ A3 - 2(400)(2.5) - 500 N _ E _ xC3 - 2.5 + 3(2.5l - 4.16? m A4 = 800(2.5) = 2000 N X04 = 6.25 I R = 2F = A1 + A2 + A3 + A4 = 1000 + 1000 + 500 + 2000 = 4500 N R = 4500 N 4 = 4.50 kN J. Ans, + C "A = A1x01 + A2x02 + A3x03 + A4x04 = 1000(1.25] + 1000(3.75) + 500(4.16?} + 2000(6.25) = 19,834 N'I Rd — M d - EA - l§¢§§£ - 4 35 -a Ans ' A ‘ a ' 4500 ' ' m - 4.50 KN d-------1 _. "' I r----- J ' 5-?5 Determine the resultant R of the system of distributed loads and locate its line of action with respect to the left support for the bean shown in Fig. P5-75. SOLUTION 3. II M II :1:- II 3 II II» II x H m n + (m z DI II II Rd %(000)(31 = 900 lb 1.0 ft %13003131 = 450 lb 5.0 ft 300(3) = 900 lb 7.5 ft BF = A1 + A2 + A3 + A4 = 900 + 450 + 900 = 2250 lb 2250 lb 2 2.25 kip + Ans. Aaxca + A2xc2 + Aaxca + A4x04 900(1.0) + 450(5.0} + 900(?.51 = 9900 ft*lb M M d = -5 - 9399 = 4.40 ft Ans. A R - 2250 ...
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