chem1b-spring04-mt2-Kubinec-soln

chem1b-spring04-mt2-Kubinec-soln - Chemistry 1B, Spring...

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Chemistry 1B, Spring 2004 Midterm 2 March 18, 2004 (90 min, closed book) Name:___________________ SID:_____________________ TA Name:________________ This exam has 39 multiple choice questions. Fill in the Scantron form AND circle your answer on the exam. Each question is worth 4 points. Note: The questions on the exam may be answered in any order. All the questions are equally weighted. Answer those you can quickly and go back to those that require more thought. Some questions may seem obvious or too simple. They are. There are no ‘trick’ questions. Questions that contain ‘mark all that apply’ may require you to mark more than one answer to get credit for that question. Page 1
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G ° = H ° - T S ° H ° = Σ H ° f (products) - Σ H ° f (reactants) S ° = Σ S ° (products) - Σ S ° (reactants) G ° = Σ G ° f (products) - Σ G ° f (reactants) S = k B lnW T = i k b,f m = i RTc for aA + bB cC + dD b a d c B A D C Q ] [ ] [ ] [ ] [ = At equilibrium, Q = K G ° = - RTln K R S T R H K ° + ° = 1 ln G ° = - nF Є º Є = Є º -RT/nF lnQ lnK = nF Є º/RT pX = - log X ] [ ] [ log HA A pK pH a + = compound vap press @ 25°C (torr) / BP°C polarity acetone, C 3 H 6 O 230 / 56 polar benzene, C 6 H 6 95 / 80 non-polar carbon tetrachloride, CCl 4 91 / 78 non-polar methanol, CH 3 OH 100 / 65 polar ethanol, CH 3 CH 2 OH 98 / 78 polar water, H 2 O 23 / 100 polar Potentially useful relations: [A] t = [A] 0 e -kt ln[A] t = ln[A] 0 – kt t 1/2 = ln2/k 1/[A] t = 1/[A] 0 + kt k = A e (-Ea/RT) ln(k 1 /k 2 ) = E a /R ( 1/T 2 – 1/T 1 ) t 1/2 = 1/[A] 0 k t 1/2 = [A] 0 /kt PV = nRT RT E kin 2 3 = M 3RT v rms = E = q + w w = - P ext V T nR E = 2 3 N 0 = 6.02214 x 10 23 mol -1 R = 2.179874 x 10 -18 J R = 3.28984 x 10 15 Hz k = 1.38066 x 10 -23 J K -1 h = 6.62608 x 10 -34 J s m e = 9.101939 x 10 -31 kg c = 2.99792 x 10 8 m s -1 Gas Constant: R = 8.31451 J K -1 mol -1 R = 8.20578 x 10 -2 L atm K -1 mol -1 T (K) = T (C) + 273.15 F = 96,485 C / mol 1 V = 1 J / C 1 nm = 10 -9 m 1kJ = 1000 J Page 2
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S ECTION 1: M IXTURES All state functions refer to the system unless otherwise noted. A table with solvent data is found under the Potentially useful relations. 1.) What is the driving force for colligative properties like freezing point depression? A) entropy B) enthalpy C) internal energy D) work E) heat 2.) Which aqueous solution has the lowest freezing point (all compounds are ionic except glucose)? A)
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chem1b-spring04-mt2-Kubinec-soln - Chemistry 1B, Spring...

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