2.5 Anatysis
of a Cjrcujt
Contajning
Depend€nt
Sources
A look at the ckcuit
in Fig.2.22
reveals
that
.
Once we know to, we can calculate
oo using Ohm's
law
.
Once we know i^, we also know the cu enl supplied by the dependent
.
The curr€nt
in the 500 V source
is
i^.
There are
thus
two unknown curents,
iA and
io.We
lleed
to construct and
solve
two independent
equations
involving
these
two currerts
to produce
From the circuit, notice
the closed path containing
the voltage source,
the 5 O resistor, and the 20 O resistor. We can apply Kircbloff's voltage
law aro nd this closed path. The resulting equation contains
the two
Nowweneed to generate
a second
equation
containing
these
two cur,
rents. Consider the closed path formed by the 20 O resistor and the
dependent
curent souice.If we attempt
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This note was uploaded on 07/05/2010 for the course EE 100 taught by Professor Boser during the Spring '07 term at Berkeley.
 Spring '07
 Boser

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