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Electric Circuits 8th Edition 102

# Electric Circuits 8th Edition 102 - The expression for R6...

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Sinrpte Resistive Circuits Now we use the constraints in Eqs. 3.50-3.52 to derive expressions for R., nb, R2, and R3 as functions of R1. From Eq. 3.51, R, RI R^=LR,=,rR,. ., = (1)'^,. Then from Eq. 3.50 we have The ratio (ir/ir) is obtained directty from Eqs. 3.59 and 3.60: tJ- Rz : Rz i2 Rr + 2R" Rr + zoRl When Eq. 3.64 js substituted into Eq. 3.63, we obtain, after some aLgebraic maniputation (see Probiem 3.69), Rr=(t+2o)' Rr. (3.65) 13.62) (3.63) (3.64) (3.66)
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Unformatted text preview: The expression for R6 as a fundjon of R1 js derived from the constraint imposed by Eq. 3.52, namety that / : \ 2 no: lrl n. \ t b / The ratio (i/i/,) js derived from Eqs.3.58 and 3.59. Thus, \ _ n ib (.\ + R2 + 2R") When Eq. 3.67 is substituted into Eq. 3.66, we obtain, after some atgebraic manipuLation Gee Probtem 3.69), ^ (L + 2c)2oR1 ^'- 4(1j "r, FinaLly, the expression for R3 can be obtained from the constnint given jn Eq. 3.50, or o.: i1)'",, (3.6e)...
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