Unformatted text preview: the unknown node voliage or. l-./ Tl'< po\re' a*uciatcd t\irh Ih. <U\ \ourccis 15ov = 50ta = -100w (delivedng). The po$er a. .ocialcd uillr Ihe r A .oLfce ic p3A= 3?,r: 3(40) = 120 w (deh'ering). We check these calculations by noiing that the total delivered power is 220 W.The total power absorbed by the three resisrors is 4(5) + 16(10) + 1(40), or 220W, as we calculalcd and as it Solving for ?J1 gives ; : ' ' = ) A '" 10 40 ' 4 0 Obiective 1-Understand and b€ able to use the node-voltag€ method For the circuit sho\ln, use the node-voltage method to lind r,1, r,2, ancl i1. How much power is delivered to the cfcuit by the 15 A source'l l ) c) Repeat (b) for the 5 A source. Answ€r: (a) 60V 10Y 10A; (b) eoo w; (c) s0w. 5r} F L - - I + ) r r o , | u o n * " n } r n , ( l...
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This note was uploaded on 07/05/2010 for the course EE 100 taught by Professor Boser during the Spring '07 term at Berkeley.
- Spring '07