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Electric Circuits 8th Edition 131

Electric Circuits 8th Edition 131 - 20i" =-16 W The 20...

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4.6 llre l,4esh-Cutrent l4ethod and Dependent sources 107 that the voltage drops are positive, the three mesh 40 + 2ta + 8(i. tb):0, ll('r, + 6 i r + 2ll 6 0 .io + \ , ! ) / + , 8 a ? , ? 6 ! r 7 ' I ' I ' \ 6(,. lb) + 4i. + 20 = 0. (4.32) Your calculator can probably solve theseequa- tions, or you can use a computer tool. Cramer's method is a useful tool when solvirrg tlree or more simultaneous equatioDs by hald. You cdr review this important tool in Appendi\ A. ReofgJnting tqs.4.32 in anriciparion of using your calculator,a computer program, or Cramer's method gives figure 4.22 ,\ The thr€€ mesh cu enis used to anatyze the circuit shown in Fi9.4.21. Thc mcsh cnrrent i" is identical with the branch crrrrcnr 'n rl'c 4rr\ source..o rheposer ds\oci- atcd with this source is prov = -40i, : -224 W. The minus sign mcans that this source is deliver- ing power to the nelwork. Thc currcnt in the 20 V source is identical 10 thc mcsh current ic: prov
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Unformatted text preview: - 20i" = -16 W. The 20 V soulce also is delivcring power to the (4.rr) 10i, - Stb + 0i. = 8i. + 20ib 6;c = oir 6lb + 101. = The three mesh currents are i b : 2 0 A , r. : 0.80 A. b) The branch curfent in the direction of the voltage 8 () resistor in the drop 0, is i" - tb. ti - 28.8 V. ,,: 8(1" lb) objective 2-llnderstand and be able to use the mesh-current method 4.7 Use lhe mesh-current method to find (a) the power delivered by the 80 V source to the cir-cuit shown and (b) the power dissipaled in the 8 O resistor. 80v Answer: (a) 400W; (b) 50w NOTE: Abo try Chaptet Problens 4.31 snd 1.32. 4.6 Tiie Mesh-eurrent Stethed amd mependent So|'srees II lhe circuilconlains dependenl sources. the nesh-currenl equalions lnusl be supplenenled by lhe appropriale conslraiil equalions. Exanple 4.5 illustrales the application of the mesh curenl method when the circuit includes a dependenl source, 30(:}...
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