Unformatted text preview: conlains live essential branches lvhere the cur'renl is uDknown and four essenlial nodes. Hence we need 10 write lwo 15 (4 1)] nesh'current equations to soive the circuit.The presence of the curreni source reduces the three unknown mesh cufents to tlvo such currents. because it cor-strains rhe difference between i" and t. to equal5 A. Hence, if we know 1. . we krow i., and vice versa. However,when we attempt to sum the voltages around eitler mesh a or rnesh c- we must inlr'oduce inlo the equations the unknown voltage across the 5 A current soulce,fhui for rnesh a: r 0 0 = 3 ( i " - l b ) + t , + 6 i a , (4.36) l00v Figure 4.25 a A circujt jttustrating nresh anatysis when a branch contains an independent cLrrrent source. l0 f) 50=4ic 1]+2(i. ib) \4.37)...
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This note was uploaded on 07/05/2010 for the course EE 100 taught by Professor Boser during the Spring '07 term at Berkeley.
- Spring '07