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Electric Circuits 8th Edition 142

Electric Circuits 8th Edition 142 - 1 18 T o fC A Next we...

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118 Techniques of Circuit Anatysis t l ,zi\ t /n ( ),, tR" - ( )u, Y I Y L -,,----a--- b +b -r--*T1." r-] '" ( t ) i f n - ( f ) , ; f n r_____l_, -r__L .... -, (D) Figure 4.39 Equivatent circuits containing a rcsistance in paratteL with a voltage source ot in series @ Using special sour€e T]ansformation I I a) Use source transfomations to find the voltage I oo in the circuit shown in Fig. 4.40. I ut nnd rne po*er aeleloped by rhe 25u v lolrage I source. I c) Find the power developed by the 8 A current I source. I I Solution I I d) We beein bv removins tbe I25 Q and l0 Q fesis- I ror". l-.*ut. the l2'5O re\islor is connecled I across the 250 V \oltage sourc€ and the l0 Q I resisror is conDected i0 reries wjlh lhe R A cur- I rent source. we also combine the .eries-con- I nected resistors into a single resistance of 20 O. I Figure 4.41 showsthe simplified circuit. Next, we can rcplace the pamllel combination of the 20O and 5O resistors with a 4O resistor. This 4 O resistor is in parallel with the 8 A source and tlerefore can be replaced with a 32 V source in series with d 4Q
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