Electric Circuits 8th Edition 142

Electric Circuits - 1 18 T o fC A Next we can rcplace the pamllel combination of w the 2 0O a nd 5 O r esistors ith a 4 O r esistor This 4 O

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118 Techniques of Circuit Anatysis tl ,zi\ t /n ( ),, tR" - ( )u, YI Y L -,,----a--- b +b -r--*T1." r-] '" (t)i fn -(f),;fn r_____l_, -r__L. ...-, (D) Figure 4.39 Equivatent circuits containing a rcsistance in paratteL with a voltage source ot in series @ Using special sour€e T]ansformation I I a) Use source transfomations to find the voltage I oo in the circuit shown in Fig. 4.40. I ut nnd rne po*er aeleloped by rhe 25u v lolrage I source. I c) Find the power developed by the 8 A current I source. I I Solution I I d) We beein bv removins tbe I25 Q and l0 Q fesis- I ror". l-.*ut. the l2'5O re\islor is connecled I across the 250 V \oltage sourc€ and the l0 Q I resisror is conDected i0 reries wjlh lhe R A cur- I rent source. we also combine the .eries-con- I nected resistors into a single resistance of 20 O. I Figure 4.41 shows the simplified circuit. Next, we can rcplace the pamllel combination of the 20O and 5O resistors with a 4O resistor.
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This note was uploaded on 07/05/2010 for the course EE 100 taught by Professor Boser during the Spring '07 term at University of California, Berkeley.

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