Ch22-p045 - 45(a The magnitude of the force acting on the proton is F = eE where E is the magnitude of the electric field According to Newtons

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a = ×× × 160 10 167 10 192 10 19 27 12 . . .. C 2.00 10 N C kg ms 4 2 c hc h (b) We assume the proton starts from rest and use the kinematic equation vv a x 2 0 2 2 =+ (or else xa t = 1 2 2 and v = at ) to show that va x == × = × 2 2 192 10 0 0100 196 10 12 5 . m . 2 di b g 45. (a) The magnitude of the force acting on the proton is
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This note was uploaded on 07/07/2010 for the course PHYS 243 taught by Professor Ew during the Fall '10 term at The Petroleum Institute.

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