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48. We assume there are no forces or forcecomponents along the
x
direction. We
combine Eq. 2228 with Newton’s second law, then use Eq. 421 to determine time
t
followed by Eq. 423 to determine the final velocity (with –
g
replaced by the
a
y
of this
problem); for these purposes, the velocity components
given
in the problem statement are
relabeled as
v
0
x
and
v
0
y
respectively.
(a) We have
/
( /
)
aq
Em emE
==
−
GG
G
which leads to
19
2
13
31
1.60 10
C
N
ˆˆ
120
j
(2.1 10 m s ) j.
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 Fall '10
 XS

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