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52. We are given
σ
= 4.00
×
10
−
6
C/m
2
and various values of
z
(in the notation of Eq. 22
26 which specifies the field
E
of the charged disk). Using this with
F
=
eE
(the magnitude
of Eq. 2228 applied to the electron) and
F = ma
, we obtain
//
aFme
Em
=
=
.
(a) The magnitude of the acceleration at a distance
R
is
a
=
e
σ
(
2 −
2
)
4
m
ε
o
= 1.16
×
10
16
m/s
2
.
(b) At a distance
R
/100,
a
=
e
σ
(10001
−
10001
)
20002
m
ε
o
= 3.94
×
10
16
m/s
2
.
(c) At a distance
R
/1000,
a
=
e
σ
(1000001
−
1000001
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This note was uploaded on 07/10/2010 for the course PHYS 211 taught by Professor Ac during the Fall '10 term at The Petroleum Institute.
 Fall '10
 AC
 Charge

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