ch22-p053 - 53. (a) Using Eq. 22-28, we find F = 8.00 105 C...

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53. (a) Using Eq. 22-28, we find G F × =− −− 8 00 10 8 00 10 600 0 240 0 0480 55 . ± . ± . ± . ± C3 . 0 01 0NC i C NCj Ni Nj . 3 ch c h bg b g b g Therefore, the force has magnitude equal to () ( ) 22 0.240N 0.0480N 0.245N. xy FF F =+ = + = (b) The angle the force F G makes with the + x axis is 11 0.0480N tan tan 11.3 0.240N y x F F θ ⎛⎞ == = ° ⎜⎟ ⎝⎠ measured counterclockwise from the + x axis. (c) With m = 0.0100 kg, the ( x , y ) coordinates at t = 3.00 s can be found by combining
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