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53. (a) Using Eq. 2228, we find
G
F
=×
×
+×
−
=−
−−
8 00 10
8 00 10
600
0 240
0 0480
55
.
±
.
±
.
±
.
±
C3
.
0
01
0NC
i
C
NCj
Ni
Nj
.
3
ch
c
h
bg
b
g
b
g
Therefore, the force has magnitude equal to
()
(
)
22
0.240N
0.0480N
0.245N.
xy
FF
F
=+
=
+
−
=
(b) The angle the force
F
G
makes with the +
x
axis is
11
0.0480N
tan
tan
11.3
0.240N
y
x
F
F
θ
⎛⎞
−
==
=
−
°
⎜⎟
⎝⎠
measured counterclockwise from the +
x
axis.
(c) With
m
= 0.0100 kg, the (
x
,
y
) coordinates at
t
= 3.00 s can be found by combining
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 Fall '10
 WX
 Force

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