# ch22-p055 - 55 We take the charge Q = 45.0 pC of the bee to...

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55. We take the charge 45.0 pC Q = of the bee to be concentrated as a particle at the center of the sphere. The magnitude of the induced charges on the sides of the grain is | | 1.000 pC. q = (a) The electrostatic force on the grain by the bee is 22 2 2 () 1 1 || ( / 2) ( / 2) ( / 2) ( / 2) kQq kQ q Fk Q q dD D D =+ = ++ where 1.000 cm D = is the diameter of the sphere representing the honeybee, and 40.0 m d µ = is the diameter of the grain. Substituting the values, we obtain 92 2 1 2 1 2 32 10 11 8.99 10 N m C (45.0 10 C)(1.000 10 C) (5.00 10 m) (5.04 10 m) 2.56 10 N . F −− =− × × × ×× × The negative sign implies that the force between the bee and the grain is attractive. The magnitude of the force is 10 | | 2.56 10 N F . (b) Let | | 45.0 pC Q ′ = be the magnitude of the charge on the tip of the stigma. The force
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