55. We take the charge 45.0 pCQ=of the bee to be concentrated as a particle at the center of the sphere. The magnitude of the induced charges on the sides of the grain is | | 1.000 pC.q=(a) The electrostatic force on the grain by the bee is 2222()11||(/ 2)(/ 2)(/ 2)(/ 2)kQqkQqFkQqdDDD⎡⎤−=+=−−⎢⎥++⎣⎦where 1.000 cmD=is the diameter of the sphere representing the honeybee, and 40.0 mdµ=is the diameter of the grain. Substituting the values, we obtain 92212123210118.99 10 N m C(45.0 10C)(1.000 10C)(5.00 10 m)(5.04 10 m)2.56 10N .F−−−⎡⎤=−×⋅××−⎢⎥××⎣⎦×The negative sign implies that the force between the bee and the grain is attractive. The magnitude of the force is 10||2.56 10NF−=×. (b) Let ||45.0 pCQ′ =be the magnitude of the charge on the tip of the stigma. The force
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