# ch22-p065 - x axis is zero; the net field component along...

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(b) From symmetry, we see in this case that the net field component along the y axis is zero; the net field component along the x axis points rightward. With θ = 60 ° , net, 2 0 cos 2 4 x Q E a πε = . Since cos(60 ° ) = 1/2, we can write this as E net = kQ/a 2 (using the notation of Eq. 21-5). Thus, E net 27 N/C. 65. (a) From symmetry, we see the net field component along the
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Unformatted text preview: x axis is zero; the net field component along the y axis points upward. With θ = 60 ° , net, 2 sin 2 4 y Q E a = . Since sin(60 ° ) = 3 /2 , we can write this as E net = kQ 3 /a 2 (using the notation of the constant k defined in Eq. 21-5). Numerically, this gives roughly 47 N/C....
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## This note was uploaded on 07/10/2010 for the course PHYS 321 taught by Professor Wb during the Fall '10 term at The Petroleum Institute.

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