This preview shows page 1. Sign up to view the full content.
73. Studying Sample Problem 223, we see that the field evaluated at the center of
curvature due to a charged distribution on a circular arc is given by
0
sin
4
E
r
θ
λ
ε
−
=
π
G
along the symmetry axis, where
λ =
=
qq
r
A
with
in radians. Here
This is the end of the preview. Sign up
to
access the rest of the document.
This note was uploaded on 07/10/2010 for the course PH 321 taught by Professor Fg during the Fall '10 term at The Petroleum Institute.
 Fall '10
 FG
 Charge

Click to edit the document details