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Unformatted text preview: PBr 3 /Et 2 O I (CH 3 ) 2 CHBr (II) Mg/Et 2 O II (CH 3 ) 2 CHMgBr (III) III + (CH 3 ) 2 C=O (CH 3 ) 2 C(OH)CH(CH 3 ) 2 H 2 O/H + To summarize. When presenting a synthesis on an exam use this format: a. Put reagents and solvents above the arrow, put the work up (if there is one) below the arrow. Separate reagents from each other with commas and from solvents with a slash (/). b. Once you write the structure of a compound you can designate it with a roman numeral and then use the numeral instead of writing the structure again. It’s easier for the grader and easier for you. Good luck on the exam. Robert Boikess Pat O’Connor Heinz Roth P.S. If you feel that the above synthesis would be very difficult for you to devise, you need to spend more time learning and understanding the reactions we have presented and you need to practice more synthesis problems....
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This test prep was uploaded on 04/03/2008 for the course CHEM 308 taught by Professor Boikess during the Winter '08 term at Rutgers.
- Winter '08
- Organic chemistry