2-10 - 2-10 In order to develop a dimensionally correct...

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2-10. In order to develop a dimensionally correct form of Eq. 2-9 the appropriate units must be included with the numerical coefficients, 585 and 1683. The units associated with the first coefficient are given by Eq. 2-10 and in this problem you are asked to find the units associated with 1683. 2-10. In order for Eq. 2-9 to be dimensionally homogeneous , the coefficient, 585 must be replaced with the quantity indicated in Eq. 2-10 and the coefficient 1683 must have a certain set of units associated with it. To begin with, that coefficient must contain the units of length. In addition, it must have the units necessary to cancel the units associated with () 0.45 / µσ ρ ll . A little thought will indicate that the dimensionally correct form of the drop diameter must be expressed as 32 0.5 2 2 0.45 0.45 0.45 1.5 2 2 0.45 6 3 5.85 gcm sd y n e dyne g 1683 10 m Pa s 1000 cm cm g D U L G  σ =  ρ  ρ µ + ρ σρ l l l l From Table 2-4 we can extract the conversion factor given by

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This note was uploaded on 07/15/2010 for the course ECM 051 taught by Professor B.g.higgins during the Winter '10 term at UC Davis.

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2-10 - 2-10 In order to develop a dimensionally correct...

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