3-7. According to the problem, the volume of the horizontal cylindrical tank is given by: (22sin2L RR=π−α−α)VL(1) where αis a function of time. If we try to calculate the value of h (high) with this definition of variables, we have: cos()2RhRα=+⋅(2) Then: • h = 0 when α= 360o• h = R or H/2 when α= 180o• h = 2R or H when α= 0 oTo calculate the variation of the αwith time: dVQdtρρ⋅=⋅(3) Now, plugging 3 into 1: ()22sin2dL RL RQdtπαα−−=
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